Class 10 Ch-5 Arithmetics Progression Exercise-5.2
Quesition1: Fill in the blanks in the following table, given that a is the first term, d the common difference, and $a_n$ the nth term of the AP:
Solution: (i) a = 7, d = 3, n = 8, $a_n$ = ?
$a_n$ = a + (n-1)d
= 7 + (8-1)3
= 7 + 21
= 7 + 21
Therefore, $a_n$ = 28
(ii) a = -18, d = ?, n = 10, $a_n$ = 0
$a_n$ = a + (n-1)d
0 = -18 + (10-1)d
18 = 9d
d = ${18}/9$
Therefore, d = 2
(iii)a = ?, d = -3, n = 18, $a_n$ = -5
$a_n$ = a + (n-1)d
-5 = a + (18-1)(-3)
-5 = a -51
a = 51 - 5
Therefore, a = 46
(iv) a = -18.9, d =2.5, n = ?, $a_n$ = 3.6
$a_n$ = a + (n-1)d
3.6 = -18.9 + (n-1)2.5
22.5 = (n-1)2.5
n-1 = ${22.5}/{2.5}$
n - 1 = 9
Therefore, n = 10
(v)a = 3.5, d = 0, n = 105, $a_n$ = ?
$a_n$ = a + (n-1)d
$a_n$ = 3.5 + (105-1)0
$a_n$ = 3.5
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